Let $\,m = 2n\!+\!1\,$ so $\,(m\!-\!1)/2 = n,\,$ Your sequence is $\,-n,-(n\!-\!1),\ldots,-1,0,1,\ldots,n\!-\!1,n,\,$ which is a sequence of $\,m = 2n+1\,$ consecutive integers. It is just the standard complete residue system (CRS) shifted left by $\,n,\,$ i.e. mapped by $\,x\mapsto x-n,\,$ which is a bijection mod $\,m.\,$
There is no standard name for this CRS, but you will sometimes see it called one of the following: least magnitude, numerically least, balanced, symmetric, signed.
Generally, by the Pigeonhole Principle, any set of $\,m\,$
integers that are pairwise incongruent $\!\bmod m\,$
form a CRS, for example any $\,m\,$ consecutive integers in an arithmetic progression which have step-size $\delta$ coptime to $\,m\,$ (OP is consecutive case where $\delta =1)$.
Remark $ $ Least magnitude residues are sometimes preferred since they may introduce simplifications, e.g. the smaller numbers may simplify calculations, e.g. using $(\pm1)^n$ vs. $9^n$ or $11^n$ in casting out nines and elevens, and as here when computing $\!\bmod\!$ on Gaussian integers $\,a+bi$ by rationalizing the modulus, where least-magnitude yields a smaller norm remainder (which enables descent in the Gaussian integer Euclidean algorithm). Further, the balanced symmetry may help exploit innate reflection (negation) symmetry, e.g. in this additive form of Wilson's theorem (sum of all elements $\!\bmod n$).
See also here and here for conventions used when extending the (Euclidean) division with remainder algorithm from $\Bbb N$ to $\Bbb Z$ (negative moduli and remainders).