I am a beginner of ordinals and I don't know any powerful techniques in it. I come across with a problem about the first uncountable ordinal like this.
Let $X$ be a set of uncountable cardinality. Using the Principle of Well Order we have a well ordering $\le$ on X(and $<$ means $\le$ but not euqual). By adding an element, which we denote by $∞$, and introducing the convention that $x < ∞$ for all $x ∈ X$, we will assume that X has a maximum with respect to $\le$.
We define $ω_1 = \text{min} \{ x ∈ X : \{y ∈ X : y < x \} \ \text{is uncountable}\} $
Clearly such a $ω_1$ exists. we define $0 = \text{min} \ X$ and intervels $[0,x], [x,y), (a,b]$ etc. in the usual sense.
Here are my questions:
(1)For any countable $A ⊂ [0, ω_1)$ there is an $x < ω_1$ so that $A ⊂ [0, x]$.(I don't know how to make use of the countability and uncountablity here)
(2)Equipped with the topology generated by open intervals, $[0, ω_1]$ is compact.
(3)A famous application of the first uncountable ordinal is to find an example of a Borel measure (with respect to the topology in (2)) that is not Radon. So how to construct a finite Borel measure $µ$ on $[0, ω_1]$ which is not a Radon measure?
Any solutions or elementary references will be appreciated!