Just to clarify definitions and notation. Let $R$ be any (commutative) ring with unity, and $\mathbb{F}$ any field. Then:
$$\text{Crit}(M) := \min_{f \in C^\infty(M,\mathbb{R})} \left| \text{Crit}(f) \right|,$$
$$\text{LS}(M) := \min \left\{ k\geq 0 \mid M = U_0 \cup \dots \cup U_k, \, \text{where each } U_i \hookrightarrow M \text{ is nullhomotopic} \right\},$$
$$\text{CL}(M) := \max \left\{ k\geq 0 \mid \exists \, \alpha_1, \dots, \alpha_k \in H^{> 0}(M; R), \, \alpha_1 \smile \dots \smile \alpha_k \neq 0 \right\},$$
$$\text{BS}(M) := \sum_{i=0}^{\dim M} b_i(M), \quad \text{where } b_i(M) = \dim_{\mathbb{F}} H_i(M; \mathbb{F}).$$
You're right about $Crit(M)\geq LS(M) \geq CL(M)$. You can check the proofs in this book, which is the main reference for the LS category.
It is also true that $Crit(M)\geq BS(M) \geq CL(M)$, taking coefficients in a field for $CL(M)$. The first inequality comes from Morse theory while the latter is due to the fact that each subproduct of the largest cup product must live in some cohomology group.
There is no relation between $LS(M)$ and $BS(M)$. Consider the torus $M=T$. Then $BS(M)=4$ but $LS(M)=2$. Now consider the real projective space $M=\mathbb{R}P^n$. Then $LS(M)=n$ but $BS(M)=1$ if $n$ is even and $BS(M)=2$ if $n$ is odd.