I am reading from Bases in Banach spaces I by I. Singer. The below defintions and results are from this book.
Let us first recall that a series $\displaystyle \sum_{i=1}^\infty x_i$ in a Banach space $E$ is called $\sigma(E, E^*)$- unconditionally Cauchy or weakly unconditionally Cauchy, if $\displaystyle \sum_{i=1}^\infty |f(x_i)| < \infty$ for all $f \in E^*.$ A series $\sum_{i=1}^\infty f_i$ in a conjugate Banach space $E^*$ is called $\sigma(E^*, E)$-unconditionally Cauchy if $\displaystyle \sum_{i=1}^\infty |f_i(x)| < \infty$ for all $x \in E.$
Lemma For a series $\displaystyle \sum_{i=1}^\infty f_i$ in a conjugate Banach space $E^*$ the following statements are equivalent:
(1.) $\displaystyle \sum_{i=1}^\infty f_i$ is $\sigma(E^*, E)$-unconditionally Cauchy.
(2.) There exists a constant $C > 0$ such that $$\sum_{i=1}^\infty |f_i(x)| \leq C \|x\| \quad (x \in E).$$
(3.) There exists a constant $C > 0$ such that $$\left\Vert\sum_{i=1}^n \alpha_i f_i \right\Vert \leq C \quad (\alpha_i = 0 \text{ or } 1, i = 1, ..., n; n= 1,2,...).$$
(4.) There exists a constant $C > 0$ such that $$\left\Vert \sum_{i=1}^n \epsilon_i f_i \right\Vert \leq C \quad (\epsilon_i = \pm{1}, i = 1, ..., n; n= 1,2,...).$$
(5.) There exists a constant $C > 0$ such that \begin{eqnarray} \left \Vert \sum_{i=1}^n \beta_i f_i \right \Vert \leq C \quad (|\beta_i| \leq 1, i = 1, ..., n; n= 1,2,...). \end{eqnarray}
(6.) $\displaystyle \sum_{i=1}^\infty f_i$ is $\sigma(E^*, E^{**})$-unconditionally Cauchy.
Proof The first implication follows applying the uniform boundedness principle to the sequence of continuous non-linear functionals $\{p_n\},$ where $$p_n(x) = \displaystyle \sum_{i=1}^n |f_i(x)| (x \in E, n = 1, 2, \ldots ).$$ ... The implication $6 \rightarrow 1$ is obvious.
Corollary For a series $\displaystyle \sum_{i=1}^\infty x_i$ in a Banach space $E$ the following statements are equivalent:
(1.) $\displaystyle \sum_{i=1}^\infty x_i$ is weakly unconditionally Cauchy.
(2.) There exists a constant $C > 0$ such that \begin{eqnarray} \nonumber \displaystyle \sum_{i=1}^\infty |f(x_i)| \leq C \|f\| \quad (f \in E^*). \end{eqnarray}
(3.) There exists a constant $C > 0$ such that \begin{eqnarray} \nonumber \left \Vert \sum_{i=1}^n \alpha_i x_i \right \Vert \leq C \quad (\alpha_i = 0 \text{ or } 1, i = 1, ..., n; n= 1,2,...). \end{eqnarray}
(4.) There exists a constant $C > 0$ such that \begin{eqnarray} \nonumber \left \Vert \sum_{i=1}^n \epsilon_i x_i \right \Vert \leq C \quad (\epsilon_i = \pm{1}, i = 1, ..., n; n= 1,2,...). \end{eqnarray}
(5.) There exists a constant $C > 0$ such that \begin{eqnarray} \nonumber \left \Vert \sum_{i=1}^n \beta_i x_i \right \Vert \leq C \quad (|\beta_i| \leq 1 , i = 1, ..., n; n= 1,2,...). \end{eqnarray}
Proof This follows by embedding $E$ in $E^{**}$ and applying the previous lemma in $E^{**}.$
In the proof of the lemma, how did he apply the uniform boundedness principle to sequence of continuous non-linear functionals?
In the proof of the lemma, to prove $(6) \rightarrow (1)$ can we proceed as the following? For $x \in E.$ Let $C : E \rightarrow E^{**}$ denote the mapping that to each $x \in E$ assigns a linear function $g$ on $E^*$ such that $g(f) = f(x)$ for all $f \in E^*.$ So, $\sum_{i=1}^\infty |f_i(x)| = \sum_{i=1}^\infty |g(f_i)| < \infty.$
How does the proof of the corollary follow from the lemma via the embedding?
Any help will be appreciated. Thanks in advance.