Let $P$ be a point group of a crystallographic group $G = (P, \mathbb{Z}^n, \alpha)$, and $N$ be its normalizer, i.e. for every $A \in N$ we get $AP=PA$. I'm interested in the structure of $N$. For dim $3$, I have constructed the normalizer for every point group and noticed that either:
- $N = GL_n(\mathbb{Q})$
- every matrix of $N$ has permutational form, e.g. $$\left(\begin{array}{rrr} 0 & x_0 & 0 \\ x_1 & 0 & 0 \\ 0 & 0 & x_2 \end{array}\right)$$ or is decomposable, e.g. $$\left(\begin{array}{rrr} -x_0 & x_0 + x_1 & 0 \\ x_1 & x_0 & 0 \\ 0 & 0 & x_2 \end{array}\right).$$
Moreover, the diagonal block of decomposable matrices coincides with the normalizer of some point group of dim 2.
Question: Why is this true? Can someone provide a reference? Is it true for higher dimensions?
Context: I'm interested in characteristic polynomials of matrices from the normalizer, particularly when they are divisible by a monic polynomial with integral coefficients. In other words, I wonder when the operator $A \in N$ has an invariant sublattice $L' < \mathbb{Z}^n$. The observation in question can reduce the problem to the lower dimensions.
Maybe there are some techniques for describing every possible index of isomorphic crystallographic subgroups?
– davendiy Aug 18 '25 at 18:47